Learn Gay-Lussac's Law tutorial, example, formula

Gay-Lussac's Law Tutorial

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Gay-Lussac's Law Tutorial

Gay-Lussac's Law:
Gay-Lussac's Law states that the pressure of a fixed amount of gas at fixed volume is directly proportional to its temperature in kelvins.

Gay-Lussac's Law Formula :
Gas Equation: P_i/T_i = P_fT_f
Initial Pressure(P_i) = P_fT_i / T_f
Initial Temperature(T_i) = P_iT_f / P_f
Final Pressure(P_f) = P_iT_f / T_i
Final Temperature(T_f) = P_fT_i / P_i
where,
P_i = Initial Pressure,
T_i = Initial Temperature,
P_f = Final Pressure. T_f = Final Temperature,

Gay-Lussac's Law Example:
Case 1: A cylinder contain a gas which has a pressure of 125kPa at a temperature of 200 K. Find the temperature of the gas which has a pressure of 100 kPa.
P_i = 125 kPa, T_i = 200 K, P_f = 100 kPa
Step 1: Substitute the values in the below final temperature equation:
Final Temperature(T_f) = P_fT_i / P_i
= (125 x 200) / 100
= 25000 / 100
Final Temperature(T_f) = 250 K
This example will guide you to calculate the final temperature manually.

Case 2: Find the final pressure of gas at 150 K, if the pressure of gas is 210 kPa at 120 K.
P_i = 210 kPa, T_i = 120 K, T_f = 150 K
Step 1: Substitute the values in the below pressure equation:
Final Pressure(P_f) = P_iT_f / T_i
= (210 x 150) / 120
= 31500 / 120
Final Pressure(V_f) = 262.5 kPa
This example will guide you to calculate the pressure manually.

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