Gay-Lussac's Law:
Gay-Lussac's Law states that the pressure of a fixed amount of gas at fixed volume is
directly proportional to its temperature in kelvins.
Gay-Lussac's Law Formula :
Gas Equation: Pi/Ti = PfTf
Initial Pressure(Pi) = PfTi / Tf
Initial Temperature(Ti) = PiTf / Pf
Final Pressure(Pf) = PiTf / Ti
Final Temperature(Tf) = PfTi / Pi
where,
Pi = Initial Pressure,
Ti = Initial Temperature,
Pf = Final Pressure.
Tf = Final Temperature,
Gay-Lussac's Law Example:
Case 1: A cylinder contain a gas which has a pressure of 125kPa at a temperature of 200 K. Find the temperature of the
gas which has a pressure of 100 kPa.
Pi = 125 kPa, Ti = 200 K, Pf = 100 kPa
Step 1: Substitute the values in the below final temperature equation:
Final Temperature(Tf) = PfTi / Pi
= (100 x 200) / 100
= 20000 / 125
Final Temperature(Tf) = 160 K
This example will guide you to calculate the final temperature manually.
Case 2: Find the final pressure of gas at 150 K, if the pressure of gas is 210 kPa at 120 K.
Pi = 210 kPa, Ti = 120 K, Tf = 150 K
Step 1: Substitute the values in the below pressure equation:
Final Pressure(Pf) = PiTf / Ti
= (210 x 150) / 120
= 31500 / 120
Final Pressure(Vf) = 262.5 kPa
This example will guide you to calculate the pressure manually.
|
|
