Combined Gas Law:
Combined Gas Law is a gas law which combines Charles's law, Boyle's law, and
Gay-Lussac's law.
Combined Gas Law Formula :
Gas Equations: PiVi/Ti = PfVf/Tf
Initial Volume(Vi) = PfVfTi / TfPi
Initial Pressure(Pi) = PfVfTi / TfVi
Initial Temperature(Ti) = PiViTf / PfVf
Final Volume(Vf) = PiViTf / TiPf
Final Pressure(Pf) = PiViTf / TiVf
Final Temperature(Tf) = PfVfTi / PiVi
where,
Vi = Initial Volume,
Pi = Initial Pressure,
Ti = Initial Temperature,
Vf = Final Volume,
Pf = Final Pressure,
Tf = Final Temperature.
Combined Gas Law Example:
Case 1: A cylinder contain a gas of volume 30 L, at a pressure of 110 kPa and a temperature of 420 K. Find the temperature
of the gas which has a volume 40 L at a pressure of 120 kPa.
Vi = 30 L, Pi = 110 kPa, Ti = 420 K, Vf = 40 L, Pf = 120 kPa Step 1: Substitute the values in the below final temperature equation:
Final Temperature(Tf) = PfVfTi /
PiVi
= (120 x 40 x 420) / (110 x 30)
= 2016000 / 3300
Final Temperature(Tf) = 610.91 K
This example will guide you to calculate the final temperature manually.
Case 2: A cylinder contain a gas of volume 10 L, at a pressure of 80 kPa and a temperature of 200 K. Find the temperature
of the gas which has a volume 20 L at a temperature of 220 K.
Vi = 10 L, Pi = 80 kPa, Ti = 200 K, Vf = 20 L, Tf = 220 kPa Step 1: Substitute the values in the below pressure equation:
Final Pressure(Pf) = PiViTf /
TiVf
= (80 x 10 x 220) / (200 x 20)
= 176000 / 4000
Final Pressure(Vf) = 44 kPa
This example will guide you to calculate the pressure manually.
This tutorial will help you dynamically to find the Combined Gas Law problems.
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